ocp考試解析:11g-1Z0-051-v9.02-023題
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23. Examine the structure proposed for the TRANSACTIONS table:
name Null Type
TRANS_ID NOT NULL NUMBER(6)
CUST_NAME NOT NULL VARCHAR2(20)
CUST_STATUS NOT NULL CHAR
TRANS_DATE NOT NULL DATE
TRANS_VALIDITY VARCHAR2
CUST_CREDIT_LIMIT NUMBER
Which statements are true regarding the creation and storage of data in the above table structure?
(Choose all that apply.)
A. The CUST_STATUS column would give an error.
B. The TRANS_VALIDITY column would give an error.
C. The CUST_STATUS column would store exactly one character.
D. The CUST_CREDIT_LIMIT column would not be able to store decimal values.
E. The TRANS_VALIDITY column would have a maximum size of one character.
F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes, seconds,
and fractions of seconds.
Answer: BC
試題解析:
VARCHAR2長度可變的字符數據(必須指定最大size,最小size為1;最大size為4000)
TRANS_VALIDITY 的VARCHAR2沒有指定size,所以錯誤。B正確。E錯誤。
CHAR 固定長度的字符數據,長度為size字節(默認和最小size為1;最大size為2000),可以不用指定size
所以CUST_STATUS的CHAR,沒有指定size,但默認size為1,不會報錯,所以A是錯誤的。C是正確的。
NUMBER [(p,s)]精度為p和小數位為s的數字(精度是十進制數字的總位數,而小數位數是小數點右側的位數,精度范圍在1~38之間,而該小數位數范圍在-84~127之間),
所以CUST_CREDIT_LIMIT 的NUMBER數據類型是可以存儲小數位的,D錯誤。
DATE:公元前4712年1月1日到公元9999年12月31日之間的日期和時間值,精確到最接近的秒。但是沒有小數秒,所以F錯誤。